*出租销售系统 5.6--算法分析

下载地址http://www.zzshow.com/bookVcd.exe

加密方式：注册码+ 反跟踪 +反汇编

功能限制：功能限制

PJ工具：W32Dasm8.93黄金版，FI2.5，OLLYDBG1.09中文修正版

PJ日期：2003-04-20

作者newlaos申明：只是学习，请不用于商业用途或是将本文方法制作的注册机任意传播，造成后果，本人一概不负。

1、先用FI2.5看一下主文件“bookVcd.exe”，没有加壳，程序是用DELPHI编写的

2、用W32Dasm8.93黄金版对bookVcd.exe进行静态反汇编，再用串式数据参考，找到"注册码错误，请与作者联系"，双击来到下面代码段。

3、该软件对TRW20001.23进行反调试，也就是说不能用TRW调试，一调试就出错。只是能用OLLYDBG1.09进行动态调试，下断BPX 00575C56(通常在注册成功与否的前面一些下断，这样，才能找到关键部分)，

输入假码: 78787878

.......

.......

* Referenced by a (U)nconditional or (C)onditional Jump at Address:

|:00575BE6(C)

|

:00575C56 6A00 push 00000000 <===你会发现在这里设才能断下来。作者为了防破解在上面的代码段动了些手脚，如果不知道，就很容易进行死胡同。

:00575C58 49 dec ecx

:00575C59 75F9 jne 00575C54

:00575C5B 53 push ebx

:00575C5C 8BD8 mov ebx, eax

:00575C5E 33C0 xor eax, eax

:00575C60 55 push ebp

:00575C61 68B35D5700 push 00575DB3

:00575C66 64FF30 push dword ptr fs:[eax]

:00575C69 648920 mov dword ptr fs:[eax], esp

:00575C6C 8D55F8 lea edx, dword ptr [ebp-08]

:00575C6F 8B8300030000 mov eax, dword ptr [ebx+00000300]

:00575C75 E8363DEDFF call 004499B0 <===算出注册码的长度

:00575C7A 8B45F8 mov eax, dword ptr [ebp-08] <===EAX=78787878

:00575C7D 8D55FC lea edx, dword ptr [ebp-04]

:00575C80 E84F35E9FF call 004091D4

:00575C85 8B45FC mov eax, dword ptr [ebp-04] <===EAX=78787878

:00575C88 8B15845E5900 mov edx, dword ptr [00595E84]

:00575C8E 8B12 mov edx, dword ptr [edx] <===EDX=3702619562

:00575C90 E847EFE8FF call 00404BDC

:00575C95 7436 je 00575CCD <===关键跳转，了也就是说，上面的EAX和EDX必须相等了

:00575C97 6A00 push 00000000

* Possible StringData Ref from Code Obj ->"error"

|

:00575C99 B9C05D5700 mov ecx, 00575DC0

* Possible StringData Ref from Code Obj ->"注册码错误，请与作者联系."

|

:00575C9E BAC85D5700 mov edx, 00575DC8

:00575CA3 A1185D5900 mov eax, dword ptr [00595D18]

:00575CA8 8B00 mov eax, dword ptr [eax]

:00575CAA E83942EFFF call 00469EE8

:00575CAF 8B8300030000 mov eax, dword ptr [ebx+00000300]

:00575CB5 E8E217ECFF call 0043749C

:00575CBA 8B8300030000 mov eax, dword ptr [ebx+00000300]

:00575CC0 8B10 mov edx, dword ptr [eax]

:00575CC2 FF92C0000000 call dword ptr [edx+000000C0]

:00575CC8 E9B5000000 jmp 00575D82

* Referenced by a (U)nconditional or (C)onditional Jump at Address:

|:00575C95(C) <===跳到这里就说明注册成功了，向上看

|

:00575CCD 8B830C030000 mov eax, dword ptr [ebx+0000030C]

:00575CD3 E8F443F4FF call 004BA0CC

:00575CD8 8B830C030000 mov eax, dword ptr [ebx+0000030C]

.......

.......(此处删除一段与算法无关的代码)

* Possible StringData Ref from Code Obj ->"information"

|

:00575D65 B9345E5700 mov ecx, 00575E34

* Possible StringData Ref from Code Obj ->"恭喜您已经注册成功，请重新运行本软件！"

|

:00575D6A BA405E5700 mov edx, 00575E40

:00575D6F A1185D5900 mov eax, dword ptr [00595D18]

:00575D74 8B00 mov eax, dword ptr [eax]

:00575D76 E86D41EFFF call 00469EE8

:00575D7B 8BC3 mov eax, ebx

:00575D7D E89A08EFFF call 0046661C

* Referenced by a (U)nconditional or (C)onditional Jump at Address:

|:00575CC8(U)

|

:00575D82 33C0 xor eax, eax

:00575D84 5A pop edx

:00575D85 59 pop ecx

:00575D86 59 pop ecx

.......

.......

4、很快就你就会发现，关键算法段不在这里。怎么办？再用串式数据参考找啊找，又发现"您已经注册成为了正版用户"，这其实就是当你点击菜单里的注册项时，程序就会判断，如果你已经注册就会显示这个，如果你没有注册就会出现要注册的提示框。呵呵，注册算法部分找到了:-)

依然是用OLLYDBG1.09进行动态调试，设断点005761B5，当你点击菜单里的注册项时，立即断下来。

------------------------********************-----------------------------

:005761B4 56 push esi

* Reference To: kernel32.GetComputerNameA, Ord:0000h

|

:005761B5 E8C60FE9FF Call 00407180 <===获取计算名称函数

:005761BA 83F801 cmp eax, 00000001

:005761BD 1BC0 sbb eax, eax

:005761BF 40 inc eax

:005761C0 84C0 test al, al

:005761C2 750C jne 005761D0 <===如果获取到就从这里跳走了

:005761C4 8BC6 mov eax, esi

:005761C6 E875C6E8FF call 00402840

:005761CB E929010000 jmp 005762F9

* Referenced by a (U)nconditional or (C)onditional Jump at Address:

|:005761C2(C)

|

:005761D0 8D45F8 lea eax, dword ptr [ebp-08]

:005761D3 8BD6 mov edx, esi <===EDX=POWERLAOS

:005761D5 E8F6E7E8FF call 004049D0

:005761DA 8B55F8 mov edx, dword ptr [ebp-08] <===EDX=POWERLAOS

:005761DD B888805900 mov eax, 00598088

* Possible StringData Ref from Code Obj ->"zjhloveling"

|

:005761E2 B93C635700 mov ecx, 0057633C <===作者内定的字符

:005761E7 E8F8E8E8FF call 00404AE4 <===将计算名和内定的字符串连起来

:005761EC 8D55F4 lea edx, dword ptr [ebp-0C]

:005761EF A188805900 mov eax, dword ptr [00598088] <===EAX="POWERLAOSzjhloveling"

:005761F4 E8DBFEFFFF call 005760D4 <===这就是算法软件机器码的CALL

:005761F9 8B55F4 mov edx, dword ptr [ebp-0C] <===EDX="981727556"这就是我的机器码了

:005761FC B888805900 mov eax, 00598088

:00576201 E82EE6E8FF call 00404834

:00576206 8BC6 mov eax, esi

:00576208 E833C6E8FF call 00402840

:0057620D 8D55F0 lea edx, dword ptr [ebp-10]

:00576210 A188805900 mov eax, dword ptr [00598088]

:00576215 E8BAFEFFFF call 005760D4 <===关键的算法CALL，F8跟进(晕，和生成机器码的CALL是一样的)

:0057621A 8B55F0 mov edx, dword ptr [ebp-10] <===EDX="3702619562"就是注册码了

:0057621D B88C805900 mov eax, 0059808C

:00576222 E80DE6E8FF call 00404834

:00576227 8B83F0020000 mov eax, dword ptr [ebx+000002F0]

.......

.......(省去一段与算法无关的代码)

:005762AA 8D45B0 lea eax, dword ptr [ebp-50]

* Possible StringData Ref from Code Obj ->"zjhloveling"

|

:005762AD BA3C635700 mov edx, 0057633C

:005762B2 E8B1F5E8FF call 00405868

:005762B7 8D55B0 lea edx, dword ptr [ebp-50]

:005762BA 58 pop eax

:005762BB E8F8F5E8FF call 004058B8

:005762C0 7521 jne 005762E3 <===这里是一个关键跳转，如果跳走就要出现注册对话框，如果不跳就显示已经注册

:005762C2 6A00 push 00000000

* Possible StringData Ref from Code Obj ->"提示"

|

:005762C4 B984635700 mov ecx, 00576384

* Possible StringData Ref from Code Obj ->"您已经注册成为了正版用户"

|

:005762C9 BA8C635700 mov edx, 0057638C

:005762CE A1185D5900 mov eax, dword ptr [00595D18]

:005762D3 8B00 mov eax, dword ptr [eax]

:005762D5 E80E3CEFFF call 00469EE8

:005762DA 8BC3 mov eax, ebx

:005762DC E83B03EFFF call 0046661C

:005762E1 EB16 jmp 005762F9

* Referenced by a (U)nconditional or (C)onditional Jump at Addresses:

|:00576291(C), :005762C0(C)

|

:005762E3 A1745E5900 mov eax, dword ptr [00595E74]

.......

.......

----------:00576215 call 005760D4 算法CALL，F8跟进)------------------------

.......

.......(省去一段与算法无关的代码)

:0057610A 8B45F4 mov eax, dword ptr [ebp-0C] <===EAX="981727556"

:0057610D E886E9E8FF call 00404A98 <===算出机器码的长度

:00576112 8BC8 mov ecx, eax

* Referenced by a (U)nconditional or (C)onditional Jump at Address:

|:005760A5(C)

|

:00576114 85C9 test ecx, ecx

:00576116 762A jbe 00576142 <===如果机器码的长度为0，就跳走。这里不跳

:00576118 BE01000000 mov esi, 00000001

* Referenced by a (U)nconditional or (C)onditional Jump at Address:

|:00576140(C) ************最关键的循环结构************

|

:0057611D 8B45FC mov eax, dword ptr [ebp-04] <===EAX="981727556"

:00576120 0FB64430FF movzx eax, byte ptr [eax+esi-01] <===依次取"981727556"字符的ASC值

:00576125 03D8 add ebx, eax

:00576127 69C3D8600B00 imul eax, ebx, 000B60D8

:0057612D BB7B000000 mov ebx, 0000007B

:00576132 33D2 xor edx, edx <===EDX清0

:00576134 F7F3 div ebx <===除以7B

:00576136 69C039300000 imul eax, 00003039 <===得到的商再乘以0x3039

:0057613C 8BD8 mov ebx, eax <===最后的EBX就是我们要的结果

:0057613E 46 inc esi

:0057613F 49 dec ecx

:00576140 75DB jne 0057611D <===向上跳构成一个循环结构

* Referenced by a (U)nconditional or (C)onditional Jump at Address:

|:00576116(C)

|

:00576142 8BC3 mov eax, ebx <===最后EBX就是我们要的注册码了，但还只是16进制的形式DCB17DAA

:00576144 33D2 xor edx, edx

:00576146 52 push edx

:00576147 50 push eax

:00576148 8B45F8 mov eax, dword ptr [ebp-08]

:0057614B E8D033E9FF call 00409520

:00576150 33C0 xor eax, eax

:00576152 5A pop edx

:00576153 59 pop ecx

:00576154 59 pop ecx

:00576155 648910 mov dword ptr fs:[eax], edx

:00576158 6875615700 push 00576175

* Referenced by a (U)nconditional or (C)onditional Jump at Address:

|:00576173(U)

|

:0057615D 8D45F4 lea eax, dword ptr [ebp-0C]

:00576160 E87BE6E8FF call 004047E0

:00576165 8D45FC lea eax, dword ptr [ebp-04]

:00576168 E873E6E8FF call 004047E0

:0057616D C3 ret

......

......

----------------------------------------------------------------------------

5、注册机源程序

=====================VB6.0源程序，在WIN98下测试通过=================

Private Sub Text1_Change()

astr1 = Text1.Text

charlen = Len(astr1)

e = 1

For i = 1 To charlen

sumtmp = Asc(Mid(astr1, i, 1))

If sumtmp < 48 Or sumtmp > 57 Then

e = 2

End If

Next

If charlen = 0 Then e = 3

If e = 1 Then

ebx = "0"

For i = 1 To charlen

sumtmp = bigadd(ebx, CStr(Asc(Mid(astr1, i, 1))))

strtmp = oct2hex(bigmul(sumtmp, "745688"))

strtmp = hex2oct(Right(strtmp, 8))

strtmp = bigdiv(strtmp, "123")

ebx = hex2oct(Right(oct2hex(bigmul(strtmp, "12345")), 8))

Next

laststr = CStr(ebx)

Else

laststr = "你输入的机器码有误"

End If

Text2.Text = laststr

End Sub

'*************上面部分就是真正的实现部分******下面只是大数运算的函数而已********

Function hex2oct(sum16)

'专门将大的16进制转为10进制的函数(目前只支持56位转换)

'函数定义是sum16为56位以下的16进制数的字符串表示形式

astr1 = UCase(sum16)

nlen = Len(astr1)

For i = 1 To nlen '检查16进制的合法性

SUMSUM = Asc(Mid(astr1, i, 1))

If (SUMSUM >= 48 And SUMSUM <= 57) Or (SUMSUM >= 65 And SUMSUM <= 70) Then

e = 1

Else

e = 2

End If

Next i

If nlen = 0 Then

e = 3

End If

Select Case e

Case 1

'在这里填入16进制转为10进制的代码段

bigsum = "0"

For i = 1 To nlen

sesum = CStr(CInt("&h" + Mid(astr1, nlen - i + 1, 1)))

For J = 1 To i - 1

sesum = bigmul(sesum, "16")

Next J

bigsum = bigadd(bigsum, sesum)

Next i

laststr = bigsum

hex2oct = laststr

Case 2

hex2oct = "你的输入非法!"

Case 3

If Option1.value = True Then

hex2oct = "16 进制实时显示"

Else

hex2oct = "10 进制实时显示"

End If

End Select

End Function

Function oct2hex(sum10)

'专门将大的10进制转为16进制的函数(目前只支持56位转换)

'函数定义是sum10为56位以下的10进制数的字符串表示形式

astr1 = sum10

e = 1 '输入操作数正确标志

For i = 1 To Len(astr1) '检查10进制的合法性

SUMSUM = Asc(Mid(astr1, i, 1))

If SUMSUM < 48 Or SUMSUM > 57 Then

e = 2

End If

Next i

If Len(astr1) = 0 Then

e = 3

End If

Select Case e

Case 1

x = Array("", "", "", "", "", "", "", "", "", "", "", "", "", "") '对数组进行定义,每个单元代表4位数，这个数组可以代表56位长度的10进制数

'*******************************************************

Do

nlen = Len(astr1) '得出10进制的长度

p = Int((nlen - 1) / 4) '得出数字占数组的个数(减去1代表数组单元的下标)，每4位数占一个数组单元

i = 0

k = 1

Do

alen = Len(astr1)

If alen <= 4 Then

k = 2

x(i) = astr1

Else

x(i) = Right(astr1, 4) '每次从低位取4位

astr1 = Mid(astr1, 1, alen - 4)

End If

i = i + 1

Loop While k = 1 '完成数据向数组的装入，每个单元为字符串，是从低位向高位的顺序

strnext = ""

strtmp = ""

modtmp = ""

r = 1 '前导去0标志

'***************************************************

For z = p To 0 Step -1 '从最后一位，也是10进制数的最高位开始

modtmp1 = CStr(CLng(modtmp + x(z)) Mod 16) '模作为与下一个数组单元相接合，再求模，直到这后的模

strtmp = CStr(Int(CLng(modtmp + x(z)) / 16))

If Len(strtmp) < 4 And r <> 1 Then '补0也是为了下次大循环的运算,如果是第一个值就不用被0了

For i = 1 To 4 - Len(strtmp)

strtmp = "0" + strtmp

Next i

End If

strnext = strnext + strtmp '得到除以16的商，准备用下一次大循环的运算初始值

modtmp = modtmp1

r = 2

Next z

'***************************************************

lastmod = Hex(Int(modtmp)) + lastmod '其实这就是16进制数了，不用再反向了

astr1 = strnext

i = 1

Do '前导去0循环

nlen = Len(astr1)

If Left(astr1, 1) = "0" Then

astr1 = Right(astr1, nlen - 1)

Else

Exit Do

End If

i = i + 1

Loop While i <= Len(astr1)

If Len(astr1) <= 2 Then '因为前已经加成4个0了，对循环退出的判断

If Len(astr1) = 0 Then '防止到下面来个CInt(astr1)类型不符

Exit Do

End If

If CInt(astr1) < 16 Then

Exit Do

End If

End If

Loop

'*****************************************************

If Len(astr1) = 0 Then

laststr = lastmod

Else

laststr = Hex(CInt(astr1)) + lastmod

End If

oct2hex = laststr

Case 2

oct2hex = "你的输入非法!"

Case 3

If Option1.value = True Then

oct2hex = "16 进制实时显示"

Else

oct2hex = "10 进制实时显示"

End If

End Select

End Function

Function bigadd(add1, add2)

'大数相加函数，参数定义add1,add2均为10进制数的字符串表示形式，限定为28位长度。

'返回值也是10进制的字符串形式。当然还有一个错误返回值是"inputerror"

'每一个0代表4位数，第一个0代表1-4位，第2个0代表5-8位，第3个0代表9-12们，类推，第7个0代表25-28位(这是从最低位开始数哟)

astr1 = add1

astr2 = add2

e = 1 '输入操作数正确标志

For i = 1 To Len(astr1) '检查第一输入的合法性

SUMSUM = Asc(Mid(astr1, i, 1))

If SUMSUM < 48 Or SUMSUM > 57 Then

e = 2

End If

Next i

For i = 1 To Len(astr2) '检查第二个输入的合法性

SUMSUM = Asc(Mid(astr2, i, 1))

If SUMSUM < 48 Or SUMSUM > 57 Then

e = 2

End If

Next i

If Len(astr1) = 0 Or Len(astr2) = 0 Then '其中任意一个操作数不能为空

e = 2

End If

If e = 1 Then

A = Array(0, 0, 0, 0, 0, 0, 0)

i = 0

k = 1

Do

alen = Len(astr1)

If alen <= 4 Then

k = 2

A(i) = CLng(astr1)

Else

A(i) = CLng(Right(astr1, 4)) '每次从低位取4位

astr1 = Mid(astr1, 1, alen - 4)

End If

i = i + 1

Loop While k = 1

'到这里完成将10进制数第4位放入数组a

wa = i '这里代表a数组里有几个数

B = Array(0, 0, 0, 0, 0, 0, 0)

i = 0

k = 1

Do

alen = Len(astr2)

If alen <= 4 Then

k = 2

B(i) = CLng(astr2)

Else

B(i) = CLng(Right(astr2, 4)) '每次取4位

astr2 = Mid(astr2, 1, alen - 4)

End If

i = i + 1

Loop While k = 1

'到这里完成将10进制数第4位放入数组b

wb = i '这里代表b数组里有几个数

C = Array(0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0) '定义最终结果数组，每一个0代表4位数

'---------------------------------相加代码段--------------------------------

If wa > wb Then

w = wa - 1

Else

w = wb - 1

End If

i = 0

tmp2 = 0

Do While i <= w '以数组最多的数决定循环次数

tmp = A(i) + B(i) + tmp2

C(i) = (tmp Mod 10000) '只留4位

tmp2 = Int(tmp / 10000) '商自动进入下一位

i = i + 1

If i = 7 Then

Exit Do

End If

Loop

C(i) = tmp2 '最后一个进位值

k = 1

For i = 13 To 0 Step -1

If C(i) <> 0 Or k <> 1 Then

ttmp = CStr(C(i))

If Len(ttmp) < 4 And k <> 1 Then '当出现某个数组中的数为0890的情况，如果不补0，就会出错了。当然也要考第一个数防止出现数字最前面出现多余的0的情况

For J = 1 To 4 - Len(ttmp)

ttmp = "0" + ttmp

Next

End If

laststr3 = laststr3 + ttmp

k = 2

End If

Next i

If k = 1 Then '两个0两相加，就可以一次都不经过

bigadd = "0"

Else

bigadd = laststr3

End If

Else

bigadd = "inputerror" '说明输入错误了

End If

'---------------------------------相加代码段结束--------------------------------

End Function

Function bigmul(mul1, mul2)

'大数相乘函数，参数定义mul1,mul2均为10进制数的字符串表示形式，限定为28位长度。

'返回值也是10进制的字符串形式。当然还有一个错误返回值是"inputerror"

'每一个0代表4位数，第一个0代表1-4位，第2个0代表5-8位，第3个0代表9-12们，类推，第7个0代表25-28位(这是从最低位开始数哟)

astr1 = mul1

astr2 = mul2

e = 1 '输入操作数正确标志

For i = 1 To Len(astr1) '检查第一输入的合法性

SUMSUM = Asc(Mid(astr1, i, 1))

If SUMSUM < 48 Or SUMSUM > 57 Then

e = 2

End If

Next i

For i = 1 To Len(astr2) '检查第二个输入的合法性

SUMSUM = Asc(Mid(astr2, i, 1))

If SUMSUM < 48 Or SUMSUM > 57 Then

e = 2

End If

Next i

If Len(astr1) = 0 Or Len(astr2) = 0 Then '其中任意一个操作数不能为空

e = 2

End If

If e = 1 Then

A = Array(0, 0, 0, 0, 0, 0, 0)

i = 0

k = 1

Do

alen = Len(astr1)

If alen <= 4 Then

k = 2

A(i) = CLng(astr1)

Else

A(i) = CLng(Right(astr1, 4)) '每次从低位取4位

astr1 = Mid(astr1, 1, alen - 4)

End If

i = i + 1

Loop While k = 1

'到这里完成将10进制数第4位放入数组a

wa = i '这里代表a数组里有几个数

B = Array(0, 0, 0, 0, 0, 0, 0)

i = 0

k = 1

Do

alen = Len(astr2)

If alen <= 4 Then

k = 2

B(i) = CLng(astr2)

Else

B(i) = CLng(Right(astr2, 4)) '每次取4位

astr2 = Mid(astr2, 1, alen - 4)

End If

i = i + 1

Loop While k = 1

'到这里完成将10进制数第4位放入数组b

wb = i '这里代表b数组里有几个数

C = Array(0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0) '定义最终结果数组，每一个0代表4位数

'---------------------------------相乘代码段开始(不考虑负数情况)--------------------------------

For i = 0 To 13

C(i) = 0

Next i

For i = 0 To 6

tmp2 = 0

For J = 0 To 6

sumtmp = A(J) * B(i) + tmp2 + C(i + J)

C(i + J) = (sumtmp Mod 10000)

tmp2 = Int(sumtmp / 10000)

Next J

C(i + J) = tmp2

Next i

k = 1

For i = 13 To 0 Step -1

If C(i) <> 0 Or k <> 1 Then

ttmp = CStr(C(i))

If Len(ttmp) < 4 And k <> 1 Then '当出现某个数组中的数为0890的情况，如果不补0，就会出错了。当然也要考第一个数防止出现数字最前面出现多余的0的情况

For J = 1 To 4 - Len(ttmp)

ttmp = "0" + ttmp

Next

End If

laststr4 = laststr4 + ttmp

k = 2

End If

Next i

If k = 1 Then 'k=1 说明一次都没经过，结果就为0

bigmul = "0"

Else

bigmul = laststr4

End If

Else

bigmul = "inputerror"

End If

End Function

Function bigdiv(mul1, mul2)

'大数相除函数，参数定义mul1,mul2均为10进制数的字符串表示形式

'这里的被除数只能在long的范围内

astr1 = mul1

nlen = Len(astr1)

astr2 = mul2

lasturn = ""

laststr = "" '最后的商

k = 1

For i = 1 To nlen

strtmp = lasturn + Mid(astr1, i, 1)

sumtmp = CLng(strtmp)

If sumtmp < CLng(astr2) Then

lasturn = CStr(strtmp)

If k = 2 Then laststr = laststr & "0"

Else

laststr = laststr & CStr(Int(sumtmp / CLng(astr2)))

lasturn = CStr(sumtmp Mod CLng(astr2))

k = 2

End If

Next

bigdiv = laststr

'lasturn就是模了

End Function

（出处：赢政天下整理收藏）

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