EbookMaker 1.21 inc c++ source keygen (4千字) 算法分析

EbookMaker 1.21

OCG

下面是关键的地方.

==============OCG=================================OCG=================================OCG

* Possible StringData Ref from Data Obj ->"1234567890ABCDEFGHIJKLMNOPQRSTUVWXYZ"

|

:004016A5 BEE5E54B00 mov esi, 004BE5E5

:004016AA F3 repz

:004016AB A5 movsd

:004016AC C745D40A000000 mov [ebp-2C], 0000000A

:004016B3 8B45D4 mov eax, dword ptr [ebp-2C]

:004016B6 40 inc eax

:004016B7 50 push eax

:004016B8 E84BD00900 call 0049E708

:004016BD 59 pop ecx

:004016BE 8945D0 mov dword ptr [ebp-30], eax

:004016C1 33DB xor ebx, ebx

:004016C3 8B45D0 mov eax, dword ptr [ebp-30]

:004016C6 8BF8 mov edi, eax

:004016C8 3B5DD4 cmp ebx, dword ptr [ebp-2C]

:004016CB 7D61 jge 0040172E

* Referenced by a (U)nconditional or (C)onditional Jump at Address:

|:0040172C(C)

|

:004016CD 837D0C00 cmp dword ptr [ebp+0C], 00000000

:004016D1 7408 je 004016DB

:004016D3 8B450C mov eax, dword ptr [ebp+0C] ; This is your inputed name

:004016D6 8B50FC mov edx, dword ptr [eax-04] ; lenth your name

:004016D9 EB02 jmp 004016DD

* Referenced by a (U)nconditional or (C)onditional Jump at Address:

|:004016D1(C)

|

:004016DB 33D2 xor edx, edx

* Referenced by a (U)nconditional or (C)onditional Jump at Address:

|:004016D9(U)

|

:004016DD 8BC3 mov eax, ebx ; start clac real sn!!(ebx is the times of loop)

:004016DF 8BCA mov ecx, edx

:004016E1 99 cdq

:004016E2 F7F9 idiv ecx

:004016E4 8BF2 mov esi, edx

:004016E6 46 inc esi

:004016E7 56 push esi

:004016E8 8D450C lea eax, dword ptr [ebp+0C]

:004016EB 50 push eax

:004016EC E8CF790A00 call 004A90C0

:004016F1 83C408 add esp, 00000008

:004016F4 8D450C lea eax, dword ptr [ebp+0C]

:004016F7 E8887D0A00 call 004A9484

:004016FC 03750C add esi, dword ptr [ebp+0C]

:004016FF 8BD3 mov edx, ebx

:00401701 4E dec esi

:00401702 81E20F000080 and edx, 8000000F

:00401708 0FBE06 movsx eax, byte ptr [esi] ;name

:0040170B 7905 jns 00401712

:0040170D 4A dec edx

:0040170E 83CAF0 or edx, FFFFFFF0

:00401711 42 inc edx

* Referenced by a (U)nconditional or (C)onditional Jump at Address:

|:0040170B(C)

|

:00401712 0FBE4C15BC movsx ecx, byte ptr [ebp+edx-44] ;table2("EBOOKMAKER")

:00401717 03C1 add eax, ecx

:00401719 B924000000 mov ecx, 00000024

:0040171E 99 cdq

:0040171F F7F9 idiv ecx

:00401721 8A441598 mov al, byte ptr [ebp+edx-68] ;table1

:00401725 8807 mov byte ptr [edi], al

:00401727 43 inc ebx

:00401728 47 inc edi

:00401729 3B5DD4 cmp ebx, dword ptr [ebp-2C] ; the end??if yes then end this loop

:0040172C 7C9F jl 004016CD

* Referenced by a (U)nconditional or (C)onditional Jump at Address:

|:004016CB(C)

|

:0040172E 8B45D0 mov eax, dword ptr [ebp-30] ;可以看见sn!!

:00401731 8B55D4 mov edx, dword ptr [ebp-2C]

this is my keygen

==============OCG=================================OCG=================================OCG

#include <iostream.h>

#include <math.h>

#include <string.h>

int main( )

{

char name[99],f[10],sn[0xa];

int i=0,l=0;

static unsigned char table2[]={"EBOOKMAKER"},table1[]={"1234567890ABCDEFGHIJKLMNOPQRSTUVWXYZ"};

cout<<endl<<" EBook Maker keygen by [OCG]"<<endl;

cout<<endl<<"Please input your name:";

cin>>name;

cout<<"Your registration code:";

l=strlen(name);

for (i=0;i<0xA;i++)

sn[i]=table1[(table2[i]+name[i%l])%0x24];

cout<<sn;

return 0;

}

==============OCG=================================OCG=================================OCG

keygen end!

bye:)

标 题:也给BCG做个广告，BCG的注册机，TC2.01通过... (347字)

发信人:XF[BCG]

时 间:2002-4-20 9:49:34

详细信息:

main()

{

char n[30],s[10];

int i;

char k1[]="EBOOKMAKER";

char k2[]="1234567890ABCDEFGHIJKLMNOPQRSTUVWXYZ";

clrscr();

printf("EBookMaker v1.21 keygen by XF[BCG]\n\n");

printf("Enter your name: ");

scanf("%s",n);

for (i=0;i<10;i++)

s[i]=k2[(k1[i]+n[i%strlen(n)])%0x24];

s[10]=0;

printf("Your RegCode is: %s\n",s);

getch();

}

（出处：赢政天下整理收藏）

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